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Explicit interface implementation 'implementation' is missing accessor 'accessor'
A class that explicitly implements an interface's property must implement all the accessors that the interface defines.
For more information, see Using Properties (C# Programming Guide).
Example
The following sample generates CS0551.
// CS0551.cs
// compile with: /target:library
interface ii
{
int i
{
get;
set;
}
}
public class a : ii
{
int ii.i { set {} } // CS0551
// OK
int ii.i
{
set {}
get { return 0; }
}
}