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The latest version of this topic can be found at Compiler Warning (level 1) C4346.
name' : dependent name is not a type
The typename keyword is required if a dependent name is to be treated as a type. This is a breaking change in the Visual C++ .NET 2003 compiler, made in order to conform to the ISO C++ standard.
For code that works the same in all versions of Visual C++, add typename
to the declaration.
The following sample generates C4346:
// C4346.cpp
// compile with: /WX /LD
template<class T>
struct C {
T::X* x; // C4346
// try the following line instead
// typename T::X* x;
};
The following samples shows other examples where the typename keyword is required:
// C4346b.cpp
// compile with: /LD /W1
template<class T>
const typename T::X& f(typename T::Z* p); // Required in both places
template<class T, int N>
struct L{};
template<class T>
struct M : public L<typename T::Type, T::Value>
{ // required on type argument, not on non-type argument
typedef typename T::X Type;
Type f(); // OK: "Type" is a type-specifer
typename T::X g(); // typename required
operator typename T::Z(); // typename required
};
and this,
// C4346c.cpp
// compile with: /LD /WX
struct Y {
typedef int Y_t;
};
template<class T>
struct A {
typedef Y A_t;
};
template<class T>
struct B {
typedef /*typename*/ A<T>::A_t B_t; // C4346 typename needed here
typedef /*typename*/ B_t::Y_t B_t2; // typename also needed here
};