PenInputPanelChangedEventHandler Delegate

Article
2012-10-19

Represents the method that handles the PanelChanged event of a PenInputPanel object.

Namespace: Microsoft.Ink
Assembly: Microsoft.Ink (in Microsoft.Ink.dll)

Syntax

'Declaration
Public Delegate Sub PenInputPanelChangedEventHandler ( _
    sender As Object, _
    e As PenInputPanelChangedEventArgs _
)
'Usage
Dim instance As New PenInputPanelChangedEventHandler(AddressOf HandlerMethod)

public delegate void PenInputPanelChangedEventHandler(
    Object sender,
    PenInputPanelChangedEventArgs e
)

public delegate void PenInputPanelChangedEventHandler(
    Object^ sender, 
    PenInputPanelChangedEventArgs^ e
)

JScript does not support delegates.

Parameters

sender
Type: System.Object

The source PenInputPanel object of this event.

e
Type: Microsoft.Ink.PenInputPanelChangedEventArgs

The PenInputPanelChangedEventArgs object that contains the event data.

Remarks

When creating a PenInputPanel object, the PanelType panel is the default panel. If the panel is changed by setting the CurrentPanel property before the pen input panel becomes active for the first time, a PanelChanged event occurs.

Examples

This C# example creates a PenInputPanel object, thePenInputPanel, and attaches it to an InkEdit control, theInkEdit. The example then adds a PanelChanged event handler to thePenInputPanel. The PanelChanged handler sets the text of the attached InkEdit control to a sentence containing the new panel type.

[C#]

//...

// Delcare the PenInputPanel object
PenInputPanel thePenInputPanel;

public Form1()
{
    // Required for Windows Form Designer support
    InitializeComponent();

    // Create and attach the new PenInputPanel to an InkEdit control.
    thePenInputPanel = new PenInputPanel(theInkEdit);

    // Add a PanelChanged event handler
    thePenInputPanel.PanelChanged +=
        new PenInputPanelChangedEventHandler(PanelChanged_Event);
}

//...

public void PanelChanged_Event(object sender,
 PenInputPanelChangedEventArgs e)
{
    // Make sure the object that generated
    // the event is a PenInputPanel object
    if (sender is PenInputPanel)
    {
        PenInputPanel theSenderPanel = (PenInputPanel)sender;

        theSenderPanel.AttachedEditControl.Text = "The panel has changed to ";
        theSenderPanel.AttachedEditControl.Text += e.NewPanelType.ToString();
    }
}

This Microsoft® Visual Basic® .NET example creates a PenInputPanel object, thePenInputPanel, and attaches it to an InkEdit control, theInkEdit. The example then adds a PanelChanged event handler to thePenInputPanel. The PanelChanged handler sets the text of the attached InkEdit control to a sentence containing the new panel type.

[Visual Basic]

'...

' Declare the PenInputPanel object
Dim thePenInputPanel As PenInputPanel

Public Sub New()
    MyBase.New()

    'This call is required by the Windows Form Designer.
    InitializeComponent()

    ' Create and attach the new PenInputPanel to an InkEdit control.
    thePenInputPanel = New PenInputPanel(theInkEdit)

   ' Add a PanelChanged event handler
   AddHandler thePenInputPanel.PanelChanged, AddressOf PanelChanged_Event
End Sub 'New

'...

Public Sub PanelChanged_Event(ByVal sender As Object, ByVal e As _
                              PenInputPanelChangedEventArgs)
    ' Make sure the object that generated
    ' the event is a PenInputPanel object
    If TypeOf sender Is PenInputPanel Then
        Dim theSenderPanel As PenInputPanel = CType(sender, PenInputPanel)

        theSenderPanel.AttachedEditControl.Text = "The panel has changed to "
        theSenderPanel.AttachedEditControl.Text += e.NewPanelType.ToString
    End If
End Sub 'PanelChanged_Event

Platforms

Windows 7, Windows Vista, Windows Server 2008 R2, Windows Server 2008

The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

Version Information

.NET Framework

Supported in: 3.0

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