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'operator' : operator has no effect; did you intend 'operator'?
If an expression statement has an operator with no side effect as the top of the expression, it's probably a mistake.
The following sample generates C4553:
// C4553.cpp
// compile with: /W1
int func()
{
return 0;
}
int main()
{
int i;
i == func(); // C4553
// try the following line instead
// i = func();
}