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expression having type 'type' would lose some const-volatile qualifiers in order to call 'function'
A variable with a specified const-volatile type can only call member functions defined with same or greater const-volatile qualifications.
The following samples generate C3848:
// C3848.cpp
void glbFunc1()
{
}
typedef void (* pFunc1)();
struct S3
{
operator pFunc1() // const
{
return &glbFunc1;
}
};
int main()
{
const S3 s3;
s3(); // C3848, uncomment const qualifier
}